Char to hex converter in c

If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. It sounds like you're still thinking that hex values are somehow different than non-hex values. They are not. Hex is just how that value is being shown to you, when you request it. So do yourself a favor and keep your values in whatever form is easiest for you to work with.

Sign up or log in Sign up using Google. Sign up using Facebook. Sign up using Email and Password. Post as a guest Name. Email Required, but never shown. The Overflow Blog. Podcast Making Agile work for data science.

Stack Gives Back Featured on Meta. New post summary designs on greatest hits now, everywhere else eventually. Visit chat. Linked 0. Related Hot Network Questions. Friday, December 3, AM. Marked as answer by prxy Friday, December 3, PM.

Friday, December 3, PM. Can you give an example on what you want exactly please. Nandkumar T. You're still getting signed bit extension. First cast to unsigned char and then cast to what you want. The output representation of the same set of bits depends upon how those bits are interpreted - which is what the casts are saying.

If the sign bit is extended and then displayed as unsigned then you'll get a very large positive number. If displayed as signed then you're get a negative number. You need to read up on integer bit representations and the difference between signed and unsigned.

It would also be helpful to see the contents of the input character array without any manipulation. So how is it possible when these values are different, that the output is the same when I convert them to hex?

The same bits exist for both 8 bits of 1s and 0s. But when you tell the compiler that it is signed, it knows that is really a negative number, or that is a negative number, etc. Because you told it to do that. They are the same number, but if you look at the ranges, the large value DOES NOT EXIST in the range for signed values for that type -- so it can only be one of the two, the large unsigned value, or the small negative value not both.

You can force cast the bits from one to the other, to see both values, but at that moment in time, its signed or not, and has one of the 2 values at that moment. Lets see if I understand this correctly now. The char is 8 bit.